1.Array.unshift()
, t6 E3 H: J$ B) E) |9 p/ B2 |- dlet fruits = ["Apple", "Banana", "Mango"];
fruits.unshift("Orange");
console.log(fruits);
// Prints ["Orange", "Apple", "Banana", "Mango"]
fruits.unshift("Guava", "Papaya");
console.log(fruits);
// Prints ["Guava", "Papaya", "Orange", "Apple", "Banana", "Mango"] 2.使用展开运算符(...)& N! p( M Y: D# T' F2 X3 S
var fruits = ["Apple", "Banana", "Mango"];
var moreFruits = ["Orange", ...fruits];
console.log(moreFruits);
// Prints ["Orange", "Apple", "Banana", "Mango"]
var someoMoreFruits = ["Guava", "Papaya", ...moreFruits];
console.log(someoMoreFruits);
// Prints ["Guava", "Papaya", "Orange", "Apple", "Banana", "Mango"]
console.log(fruits);
// Prints ["Apple", "Banana", "Mango"] 3.使用 Array.concat()
2 n! j+ H0 H# L7 `4 f0 f 我们还可以使用concat()方法在开头连接两个(或更多)数组。
$ N3 P- v0 j( A4 ~) a. x; Dvar fruits = ["Apple", "Banana", "Mango"];
var moreFruits = ["Orange"];
var someoMoreFruits = ["Guava", "Papaya"];
var allFruits = someoMoreFruits.concat(moreFruits, fruits);
console.log(allFruits);
// Prints ["Guava", "Papaya", "Orange", "Apple", "Banana", "Mango"]
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