1.Array.unshift()
1 X1 _% l8 T' y2 F8 I/ Ilet fruits = ["Apple", "Banana", "Mango"];
fruits.unshift("Orange");
console.log(fruits);
// Prints ["Orange", "Apple", "Banana", "Mango"]
fruits.unshift("Guava", "Papaya");
console.log(fruits);
// Prints ["Guava", "Papaya", "Orange", "Apple", "Banana", "Mango"] 2.使用展开运算符(...)
7 K; {0 n) e' q( u! Wvar fruits = ["Apple", "Banana", "Mango"];
var moreFruits = ["Orange", ...fruits];
console.log(moreFruits);
// Prints ["Orange", "Apple", "Banana", "Mango"]
var someoMoreFruits = ["Guava", "Papaya", ...moreFruits];
console.log(someoMoreFruits);
// Prints ["Guava", "Papaya", "Orange", "Apple", "Banana", "Mango"]
console.log(fruits);
// Prints ["Apple", "Banana", "Mango"] 3.使用 Array.concat()
+ @! ?; f0 ~6 ^7 h# D" l* {( a 我们还可以使用concat()方法在开头连接两个(或更多)数组。
5 `4 h( o# n- b2 Z) b- pvar fruits = ["Apple", "Banana", "Mango"];
var moreFruits = ["Orange"];
var someoMoreFruits = ["Guava", "Papaya"];
var allFruits = someoMoreFruits.concat(moreFruits, fruits);
console.log(allFruits);
// Prints ["Guava", "Papaya", "Orange", "Apple", "Banana", "Mango"]
|